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Stephan Bergmann yazdı
Assume thread t1 creates OUString s, then spawns thread t2, then t2 acquires s, then t2 signals via a channel that does not necessarily involve memory synchronization (e.g., writes a byte into a pipe which t1 reads), then t1 releases s and can still see a refCount of 1 instead of 2. Change-Id: I31047a1a6cc8fccc401a87849f5c3cee3642d803
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