Remove redundant condition

Change-Id: I21385a37a5e2107069919250dd35812ac5972422
Reviewed-on: https://gerrit.libreoffice.org/68411
Tested-by: Jenkins
Reviewed-by: Noel Grandin <noel.grandin@collabora.co.uk>

cui/source/dialogs/SpellDialog.cxx

@@ -1851,7 +1851,7 @@ svx::SpellPortions SentenceEditWindow_Impl::CreateSpellPortions() const
             aRet.push_back(aPortion1);
 
         }
-        else if(!aBreakPositions.empty())
+        else
         {
             LanguagePositions_Impl::iterator aStart = aBreakPositions.begin();
             //start should always be Null